Answer:
This question lacks options, options are:
A) ATP
B) NADP
C) Pryuvate
D) glucose
E) acetyl-CoA.
The correct answer is C) Pyruvate.
Explanation:
Pyruvate is a very important compound for the cell since it is a key substrate for energy production and glucose synthesis (neo-glycogenesis), that is, pyruvate is the end product of glucose breakdown in glycolysis. Before entering the mitochondria, it can be converted to lactate, through an anaerobic reaction (in the absence or under oxygen supply) of low performance in energy production, when the main pathway is interfered with. It can also be converted to the amino acid alanine. Within the mitochondria, it can be transformed, by pyruvate dehydrogenase (PDH), into acetyl-coenzyme A (acetyl-CoA), the entry point (substrate) of the Krebs cycle. In addition, by means of pyruvate carboxylase, it can be transformed into oxalacetate, which constitutes the first step in neoglycogenesis.
Conifer tree is the tree that the leaf is slender like needle, it is evergreen tree more, material is general softer, some contain colophony , reason calls soft material again, its grows in elevation 100 ~ 1500 meters commonly, have economy and ornamental value.Conifers appeared 280 million years ago before any other trees.Conifers are believed to be the oldest trees on earth。
Answer:
The cross is as follows:
P: D/d × d/d
Explanation:
Half of the F1 progeny are mutant. The mutation results in 3 cotyledons is dominant and the original mutant is heterozygous.
If D denotes the mutant allele and d denotes the wild type allele.
The cross is as follows:
P: D/d × d/d
F1 denotes D/d three cotyledons
d/d denote two cotyledons
Answer:
a) Yes
b) Yes
c) Yes
d) Yes
Explanation:
a.
In the exons?
Yes mutant site will be expected. It will transcript-ed as well and it can be a polypeptide depending on the mutation type.
b.
In the intron?
Yes mutant site will be expected. It will be transcript-ed as well and it cannot be a polypeptide
c.
In the promoter?
Yes mutant site will be expected. It will not be transcript-ed and it cannot be a polypeptide
d.
In the intron-exon boundary?
Yes mutant site will be expected. It will be transcript-ed and it cannot be a polypeptide
Answer:
I don't understand the question
