Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
So the first four terms of the sequence are
2, 6, 10, 14
3.30 x 5 = 16.50
4.30 x 7 = 30.10
30.10 + 16.50 = $46.60
Answer:15 candy bars are solddd
Step-by-step explanation:
Answer: m< MIH is 34°
M< AVM is 70°
And the angle of the obtuse angle formed at the intersection of AV and HI is 104°
Step-by-step explanation: starting with m<MIH, AH is parallel to MI, so that would make the same angle H has the same for I. (34°)
Next is m<AVM. The angle of m<LAH is 110°. So the angle of m<HAV (because it's supplementary of it) is 70 (110+70=180). Which makes m<AVM 70° since it's vertical to each other.
Since we got those answers, the next one you just plug it in, and the answer would be 104°
