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MakcuM [25]
3 years ago
9

Solve each equation. 7) 18 =-2+a 8) -7= m - 12 9) -8(7 + 7n)=-336 10) -140=-7(-4+36)

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Answer:

7) a= 20

8) m= 5

9)n = 5

10) b = 8

Step-by-step explanation:

7) 18+2=-2+2+a

>> 20 = a >> a = 20

18 + 2 = 20 so that isolates the variable leaving a = 20

8) -7+12 = m -12+12

>>> 5 = m >> m = 5

-7 + 12 = 5 so that again isolates the variable leaving m = 5

9) <u>-8(7</u> + <u>7n</u>) = -336

>> -56+56 + -56n = -336+56

>>> -56n/-56 = -280/-56

>>>> n = 5

use distributive property, cancel out necessary numbers, isolate the variable. leaving n = 5.

10) -140 = <u>-7(-4 </u>+ <u>3b)</u>

>>  -140 = 28 - 21b >> -140-28 = -21b +28-28 ( flipped the numbers)

>>>  -168/-21 = -21b /-21

>>>> 8 = b >> b =8

Hope it helps!

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Answer:

Option E is correct.

12 pairs of socks and 15 pairs of shorts did team buy each year.

Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

⇒5x+17y = 315                   .....[1]

It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

⇒6x + 18y = 342                   .....[2]

Multiply equation [1] by 6 both sides we get;

30x+102y = 1890                 .......[3]

Multiply equation [2] by 5 both sides we get;

30x +90y = 1710                   .....[4]

Subtract equation [4] from [3] we get;

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Divide both sides by 168 we get;

y = 15

Substitute the given values of y =15 in [1] we get;

5x+17(15) = 315

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Subtract 255 from both sides we get;

5x = 60

Divide both sides by 5 we get;

x = 12

Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.

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