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2 years ago

Are the fractions 5/6, 5/7, 5/8, and 5/9 and arranged in order from greatest to least? Explain.

Mathematics

1 answer:

VashaNatasha [74]2 years ago

3 0

No

Step by step
5/9 5/8 5/7 5/6

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Can someone please help me on this question and show the work if you can?

Studentka2010 [4]

Answer:

it is a 60 30 90 triangle so basically 2y is = x

21² + y² = x²

441 + y² = x²

y = x/2 (2y = x)

441 + x²/4 = x²

4x² = 1764 + x²

3x² = 1764

x = exact is 24.248711306 simplied square root would just be 14√3

2y = 14√3

y = 7√3

exact wouldd be 12.124355653

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2 years ago

How do I simplify this problem

ziro4ka [17]

8: 17/24
9: 7/48
10: 5 1/4
11: 1.75

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2 years ago

8. Write a multiplication expression<br> that you can use to find

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Answer:

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Step-by-step explanation:

I really dont understand

8 0

3 years ago

Read 2 more answers

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

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1 year ago

What is an out lire in math

lara31 [8.8K]

A value that "lies outside" (is much smaller or larger than)

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3 years ago