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3 years ago

1) A furlong is 1/8 of a mile. What part of a mile is 6 furlongs?

Mathematics

2 answers:

mojhsa [17]3 years ago

8 0

Answer:

3/4 of a mile

Step-by-step explanation:

1 furlong = 1/8 mile

======== ====

6 forlongs = x

cross multiply

1*x = 6 * (1/8)

x = 6/8

reduce 6/8. Divide top and bottom by 2

x = 3/4

Semmy [17]3 years ago

5 0

Answer:

6/8 of a mile,

Step-by-step explanation:

if one furlong is 1/8 of a mile, the 6 shall be 1/8 added to itself 6 times, therefore it shall be 6/8.

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TEA [102]

Answer:

A. 35 deg

Step-by-step explanation:

The triangles are congruent bu HL.

m<RCD = m<PCD = 35 deg

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Mrac [35]

Answer:

Step-by-step explanation:

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3 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

In the right triangle ABM

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

In the right triangle BMC

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

Find the length of DC

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

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3 years ago

Name the property the equation illustrates.

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3 years ago

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Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The

Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

$x = 3y$

According to the cost we have:

$3x + 7y = 6000$

Substituting the first in the second equation we have:

$3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375$

Thus, the concert was 375 adults.

On the other hand we have:

$x = 3 (375) = 1125$

Thus, the concert was 1125 children.

In total they were:

$375 + 1125 = 1500$ people

ANswer:

The concert was 1500 people

3 0

3 years ago