Answer:
pretty sure C
Step-by-step explanation:
sorry if im incorrect information
Answer:
x<12
Step-by-step explanation:
Let's solve your inequality step-by-step.
−3<
x/
−4
Step 1: Simplify both sides of the inequality.
−3<
−1/
4
x
Step 2: Flip the equation.
−1/
4
x>−3
Step 3: Multiply both sides by 4/(-1).
(
4/
−1
)*(
−1/
4
x)>(
4
/−1
)*(−3)
x<12
Answer:
x<12
Answer:
97.5 m^2
Step-by-step explanation:
Given data
Length = 65m
Width= 30m
We are told that the width of the path= 1.5m
Hence the area of the path is
=65*1.5
=97.5 m^2
Let
be the random variable for the time a given person from the population spends sleeping. With
we have

where
.


Rounded to the nearest whole number, that comes out to about 31%.
Answer:
Volume of the similar sphere be 64 :343 .
Option (D) is correct.
Step-by-step explanation:
Formula

As given
The volumes of two similar spheres given that the ratio of their radii is 4:7 .
Let us assume that the x be the scalar multiple of the radi .
Radius of first sphere = 4x
Radius of second sphere = 7x
Putting the values in the formula




Thus


Therefore the ratio of the volume of the similar sphere be 64 :343 .
Option (D) is correct .