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Arturiano [62]
3 years ago
11

whats the answer to at the beach, you would like to fill 5 buckets with seashells. you have 8minutes to do so. if you set a stea

dy pace, how much of a bucket should you fill each minute?
Mathematics
1 answer:
Musya8 [376]3 years ago
6 0
8 ÷ 5 = 1.6, this is the answer because BUCKET PER MINUTE (Put in fraction form 8/5 and then divide and into 5)
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Guys I am going to run out of points. Help with 19?<br> I don't need an explanation.
nasty-shy [4]

Answer:

A.) 20x + 2y = 500

B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.

C.) x-intercept = 25; How many T-shirts they can sell at most

Step-by-step explanation:

2y - 500 = -20x

20x + 2y - 500 = 0

20x + 2y = 500

y-intercept = 250; its meaning is how many boxes of pencils they started with.

20x + 2y = 500

20(0) + 2y = 500

2y = 500

2y/2 = 500/2

y = 250

x-intercept = 25; How many T-shirts they can sell at most

20x + 2y = 500

20x + 2(0) = 500

20x = 500

20x/20 = 500/20

x = 25

4 0
2 years ago
A French class has a total of 31 students. The number of males is 7 more than the number of females. How many males and how many
Inessa05 [86]

Answer:

12

Step-by-step explanation:

5 0
2 years ago
If ΔABC ≅ ΔEDF where the coordinates of A(0, 2), B(2, 4), and C(2, −1), what is the measure of DF?
allsm [11]

Answer:

C. 5

Step-by-step explanation:

Since Triangle ABC is congruent to EDF it mean that the sides are the same so the length of BC is congruent to the length of DF:

distance formula:

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(2 - 2)^2 + (-1 - 4)^2

d = √(0)^2 + (-5)^2

d = √0 + 25

d = √25

d = 5

4 0
3 years ago
Read 2 more answers
Set up and solve the following using dimensional analysis.
Softa [21]
1).  Multiply (5400 inches) by (1 foot / 12 inch) then by (1 mile / 5280 foot).

      (See explanation at the bottom)

         =      (5400 inch) x (1 foot / 12 inch) x (1 mile / 5280 foot)

         =      (5400 x 1 x 1 / 12 x 5280)  (inch - foot - mile / inch - foot) 

         =          0.0852  mile  


2).  Multiply (16 week) by (7 day/week) then by (24 hour/day)
       then by (60 minute/hour) then by (60 sec/minute).

3).  Multiply (54 yards) by (3 foot/yard) then by (1 meter/3.28 foot)
       and then by (1000 mm/meter)

4).  Multiply (36 cm/second) by (3600 second/hour) then by (1 meter/100 cm)
      then by (1 mile/1609.3 meter).

5).  Look up how many grams in a pound  ('P')
       Look up how many mL in a gallon       ('G')

      Multiply (1.09 g/mL) by ( 1 pound/ P gram) then by (1 gallon/ G mL)

6).  Multiply (32 foot/sec) by (1 meter / 3.28 foot) then by (60 sec/minute).


Each time I told you to multiply by something, it was always a fraction
where the numerator and denominator are equal, like (60 seconds/minute)
or (1 foot / 12 inch).  Since the top and bottom of the fraction are equal, the
value of the fraction is ' 1 ' , and multiplying by it doesn't change the value,
it only changes the units ... that's what this whole exercise is about.
When you multiply, KEEP the units in the product, and then, after you multiply, you can 'cancel' units out of the top and bottom of the product.
Like if you have 'feet' on top and bottom, just cross them out.  When you're done, if you did it correctly, the last unit you end up with will be the one you want.      
4 0
3 years ago
A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
7 0
2 years ago
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