Which points are distance of 5 units from the x-axis
1 answer:
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Answer:
Step-by-step explanation:
To find the length and width of the figure given the equation (s-2) (s+6) = 153, we will find the equivalent value of s by factoring.
(s-2) (s+6) = 153
s²+6s-2s-12 = 153
s²+4s-12-153 = 0
s²+4s-165 = 0
s²+15s-11s-165 = 0
s(s+15)-11(s+15) = 0
s+15(s-11) = 0
s+15 = 0 and s-11 = 0
s = -15 and 11
s cannot be negative
Hence s = 11
The length of the figure is s
The width is s+6
Length = 11
Width = 11+6 = 17
Hence the length of the figure is 11 and the width is 17
