Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Recall that an equation in slope-intercept form is as follows:
where m is the slope of the line, and (0,b) is the y-intercept.
Substituting m=-6, and b=-1/2 we get:
Simplifying the above result we get:
Answer:
Answer:
hehehehehheh
Step-by-step explanation:
Shiny roachnoises :P
Answer:
Zero
Step-by-step explanation:
Answer:
4 rows of 7 plants each
Step-by-step explanation:
To find the number of plants in each row between 5 and 12 requires us to find the factors of the total 28.
28 has factors 1,28 and 2,14 and 4,7. Only 4,7 has a number between 5 and 12. There are 4 rows of 7 plants.
