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SOVA2 [1]
3 years ago
6

The sum of two consecutive odd integers is − 68 -68 . Find the numbers.

Mathematics
1 answer:
algol133 years ago
8 0

Answer:

Step-by-step explanation:

let one no. be 'x'.

the other no. is (x+2)

therefore the eq. is:

x+x+2= -68

2x+2= -68

2x = -68-2

    = -70

x= -70/2

 = -35

one number is -35

other number is (x+2) = -35 + 2

                                     = -33

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How to solve a one step equation of R+3= -6 1/2 <br> please show all the work
IgorC [24]
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer:  R = (-19)/2
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3 years ago
What are the solutions to the quadratic equation below? X^2-8x+16
leva [86]

(₋4)²

how i got it -

1st i used the sum-product pattern

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then, found the common fact from the two pairs

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rewrite in factored form

(x-4)-4(-4)

(-4) (-4)

combine to a square

(-4) (-4)

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