We have to define an interval about the mean that contains 75% of the values. This means half of the values will lie above the mean and half of the values lie below the mean.
So, 37.5% of the values will lie above the mean and 37.5% of the values lie below the mean.
In a Z-table, mean is located at the center of the data. So the position of the mean is at 50% of the data. So the position of point 37.5% above the mean will be located at 50 + 37.5 = 87.5% of the overall data
Similarly position of the point 37.5% below the mean will be located at
50 - 37.5% = 12.5% of the overall data
From the z table, we can find the z value for both these points. 12.5% converted to z score is -1.15 and 87.5% converted to z score is 1.15.
Using these z scores, we can find the values which contain 75% of the values about the mean.
z score of -1.15 means 1.15 standard deviations below the mean. So this value comes out to be:
150 - 1.15(25) = 121.25
z score of 1.15 means 1.15 standard deviations above the mean. So this value comes out to be:
150 + 1.15(25) = 178.75
So, the interval from 121.25 to 178.75 contains the 75% of the data values.
Answer:
7. 4^2 = 6
8. 7^2 = 49
9. 6^4 =1296
10. 1^2 = 1
11. 5^3 =125
12. 1^3 =1
Step-by-step explanation:
Answer: 20
Step-by-step explanation:
So what I did was divide the pages by the hours and got 20
but, when it starts with 20 pages an hour you have... 20
(-2,3) to (2,-3)
6^2 + 4^2 = c^2
c = 7.21
————
(-2,3) to (1,5)
2^2 + 3^2 = c^2
c = 3.61
————
3.61 * 7.21 = approx. 26.03
The area is 26.03un^2
Answer:
10
Step-by-step explanation:
