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3 years ago

Write an expression with a value of 12.it should contain four numbers and two different operations

Mathematics

1 answer:

sergey [27]3 years ago

4 0

Roughly what I gave your doppelganger (you + 1) a few minutes ago . . .

[ (4 + 3)² - 1 ] divided by (7 - 3) .

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3 1/5 less than 1, equal to 1, or greater than 1?

Contact [7]

Answer:

Greater than 1

Step-by-step explanation:

5 0

3 years ago

How many sides does a regular polygon have if each exterior angle measures 30 degree

Nataly [62]

As the exterior angles always add up to 360, you can find the number of sides by dividing 360 by the measure of your exterior angle, 30. This gives you 360/30=12, meaning your polygon has 12 sides.

5 0

3 years ago

1. A bicycle that normally sells for $150 is on sale of 35% off. What is the sale price of the bicycle?

Ivan

Answer:

The sale price would be $102.50

Step-by-step explanation:

To find this amount, start by multiplying the price by the sale percentage,

$150 * 35% = $47.50

Now subtract that amount from the original.

$150 - $47.50 = $102.50

4 0

3 years ago

Mx^{2} + n x^{2} when m = -5 and n = 3 what is the value of the expression

Vinil7 [7]

$|(-5)^2+3^2|=|25+9|=|34|=34$

8 0

1 year ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

3 years ago