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Gwar [14]
3 years ago
11

4k+mn=n-3; solve for n

Mathematics
1 answer:
solong [7]3 years ago
8 0
Since we are solving for n you have to isolate the n. Therefore, you want all the variables with an n in it on one side and all the variables without an n on the other side:) :
4k+3= -mn+n (There were a change in signs because for example you moved the -3 to the other side, therefore it can only be a negative on one side so now you have to change the sign to a positive:) hope you got that)
That would've been your answer because you cannot do anything else...Hope this helped :)

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Assume that advanced students average 93% on an achievement test and regular students averaged 75%. If 100 advanced students and
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Average (mean) = (sum of all the data) / (# of data)

sum of all the data = (average)(# of data)

Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300

and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500

Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %

Now if there are x # of advanced students and y # of regular students, then

x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)

The second equation can be simplified to x - 2y = 0

Subtracting the two equations yields

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Therefore you would need 60 advanced and 30 regular students.
7 0
3 years ago
Casey puts wrapping paper around a gift box. She wants to tie a ribbon
kkurt [141]
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A ratio of shirts to belts in a persons closet is 3:2 if there are 24 shirts in the closet how many belts are in the closet?
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Answer: there are 16 belts.

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6 0
2 years ago
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A). 4r − 3

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

Let

x = original price of the game

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x = 27 ÷ 3/2

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x = £18

Therefore, the original price of the game is £18

4 0
2 years ago
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