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3 years ago

11

4k+mn=n-3; solve for n

1 answer:

solong [7]3 years ago

8 0

Since we are solving for n you have to isolate the n. Therefore, you want all the variables with an n in it on one side and all the variables without an n on the other side:) :
4k+3= -mn+n (There were a change in signs because for example you moved the -3 to the other side, therefore it can only be a negative on one side so now you have to change the sign to a positive:) hope you got that)
That would've been your answer because you cannot do anything else...Hope this helped :)

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Solve for x X - 1/2 (8 - x) = x + 3(4 - x) - x<br> A) -32/9<br> B) -9/32<br> C) 32/9<br> D) 9/32

Greeley [361]

Option C

$x = \frac{32}{9}$

<em><u>Solution:</u></em>

$x - \frac{1}{2} \times (8 - x) = x + 3(4 - x) - x$

We have to solve for "x"

From given,

$x - \frac{1}{2} \times (8 - x) = x + 3(4 - x) - x$

Solve for brackets

Use distributive property

a(b + c) = ab + ac

Therefore,

$x - 4 + \frac{x}{2} = x + 12 - 3x - x$

Combine the constants

$x + \frac{x}{2} = x - x - 3x + 12 + 4\\\\x + \frac{x}{2} = -3x + 16$

Move the variables to left side of equation

$x + \frac{x}{2} + 3x = 16$

Combine the like terms

$2x + x + 6x = 32\\\\9x = 32\\\\x = \frac{32}{9}$

Thus option C is correct

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