Please just answer number 5

Simplify the ratio 12:18

denis-greek [22]

Answer: 2:3

Step-by-step explanation:

The fraction 12/18 is equivalent to 2/3.

3 0

4 years ago

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Find the midpoint of the line segment with end coordinates of (2,0) and (8,8)

viva [34]

Answer:

Step-by-step explanation:

$Midpoint = \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(2,\:0\right),\:\\\left(x_2,\:y_2\right)=\left(8,\:8\right)\\\\=\left(\frac{8+2}{2},\:\frac{8+0}{2}\right)\\\\=(\frac{10}{2} , \frac{8}{2} )\\\\Simplify\\\\(5,4)$

4 0

3 years ago

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If the arc length of a sector in the unit circle is 4.2, what is the measure of the angle of the sector

____ [38]

S = rθ
4.2 = 1*θ

The central angle (θ) is 4.2 radians.

7 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u> $\mu$ <u> is; </u>

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

<u>98% confidence interval for</u> $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago

Katy has 46 missing assignments in math class and 60 missing assignments in history. She has 106 missing assignments in total. K

guapka [62]

Answer:

She needs to do at least 8 a day

Step-by-step explanation:

4 0

3 years ago

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