When a 757 passenger jet begins its descent to the Ronald Reagan National Airport in Washington, D.C., it is 3900 feet from the

Question

3 years ago

11

ground. Its angle of descent is 6 degrees.
How far must the plane fly to reach the run way?
A. 37,106 ft
B. 37,310.4 ft
C. 23,456.6 ft
D 2,492.7 ft

2 answers:

mylen [45] · Answer 1 · 2022-02-15T04:57:25+03:00

mylen [45]3 years ago

5 0

Answer:

D

Step-by-step explanation:

Svetradugi [14.3K] · Answer 2 · 2022-02-15T02:36:58+03:00

Answer:

Option A. 37106 ft.

Step-by-step explanation:

Given: An 757 passenger jet at the height of 3900 feet from the ground means vertical height = 3900 feet.

Angle of descent to the airport in Washington,D.C. is 6 degrees.

To find: Horizontal distance the plane will cover to reach the run way.

Solution: As we know tan ∅ = $\frac{Height}{Base}$

Then tan 6° = $\frac{3900}{x}$

0.105 = $\frac{3900}{x}$

x = $\frac{3900}{.105}$

x = 37106 ft