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sergejj [24]
3 years ago
11

When a 757 passenger jet begins its descent to the Ronald Reagan National Airport in Washington, D.C., it is 3900 feet from the

ground. Its angle of descent is 6 degrees.
How far must the plane fly to reach the run way?
A. 37,106 ft
B. 37,310.4 ft
C. 23,456.6 ft
D 2,492.7 ft
Mathematics
2 answers:
mylen [45]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Svetradugi [14.3K]3 years ago
3 0

Answer:

Option A. 37106 ft.

Step-by-step explanation:

Given: An 757 passenger jet at the height of 3900 feet from the ground means vertical height = 3900 feet.

Angle of descent to the airport in Washington,D.C. is 6 degrees.

To find: Horizontal distance the plane will cover to reach the run way.

Solution: As we know tan ∅  = \frac{Height}{Base}

Then tan 6° = \frac{3900}{x}

0.105 = \frac{3900}{x}

x = \frac{3900}{.105}

x = 37106 ft

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