-2{-7-2[3 squared + 2 to the power of 4]-8÷4}
1 answer:
You might be interested in
Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
Answer:
The answer is option B.
Step-by-step explanation:
Hope this helps you