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scoundrel [369]
3 years ago
9

Help please Brainiest answer to whoever is first

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

84 inches squared

Greeley [361]3 years ago
6 0

Step-by-step explanation:

perimeter = 6+7+5+10+15

= 43

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A church building fund has $3.2 million in it, which is 60% of the amount necessary for the project. What
Alexandra [31]

Answer:

$5.4 Million

Step-by-step explanation:

3.2 mill/x = 60/100

3.2 mill x 100 = 60x

320 mill = 60x

x = 5.3333 million, rounded up to 5.4 million

5 0
3 years ago
Which of the following statements contain a variable? Check all that apply.
Roman55 [17]
B
Explanation:

A Variable is a symbol for a number we don't know yet. We don’t know the number of colors on the page.
4 0
3 years ago
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

3 0
3 years ago
Give the unit rate for the better deal.<br><br> $81<br> 25 gal<br> or <br> $62.05<br> 20 gal
Elan Coil [88]

Answer:

$62.05 for 20 gallons

Sorry if I didn't get it correct. I don't really understand how you worded your question. <3

Step-by-step explanation:

$81 for 25 gallons =

81/25 = $3.24 for 1 gallon

$62.05 for 20 gallons =

62.05 / 20 = $3.10 for 1 gallon

6 0
3 years ago
Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by
V125BC [204]
For this case we have the following functions:
 y1 = x + 2&#10;&#10;y2 = x ^ 2 + 2&#10;&#10;y3 = 2 ^ x
 
 When x = 0 we have:
 For y1:
 y1 = 0 + 2&#10;&#10;y1 = 2
 For y2:
 y2 = 0 ^ 2 + 2&#10;&#10;y2 = 0 + 2&#10;&#10;y2 = 2
 Therefore, we have to:
 y1 = y2&#10;

 When x = 5 we have:
 For y2:
 y2 = 5 ^ 2 + 2&#10;&#10;y2 = 25 + 2&#10;&#10;y2 = 27
 For y3:
 y3 = 2 ^ 5&#10;&#10;y3 = 32
 Therefore, we have to:
 y2 \ \textless \ y3&#10;

 When x = -1 we have:
 For y1:
 y1 = -1 + 2&#10;&#10;y1 = 1
 For y2:
 y2 = (-1) ^ 2 + 2&#10;&#10;y2 = 1 + 2&#10;&#10;y2 = 3&#10;
 For y3:
 y3 = 2 ^ {-1}&#10;&#10;y3 = 1/2&#10;&#10;y3 = 0.5
 Therefore, we have to:
 y3 \ \textless \ y1 \ \textless \ y2&#10;

 Answer:
 
When x = 0, y1 = y2
 
When x = 5, y2 <y3
 
When x = -1, y3 <y1 <y2
4 0
4 years ago
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