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horsena [70]
3 years ago
13

What is the best approximation of the area of a circle with a diameter of 17 meters? Use 3.14 to approximate pi. 53.4 m² 106.8 m

² 226.9 m² 907.5 m²
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
8 0
R = 17/2 =8.5 m
A = 3.14 x (8.5)^2
A = 3.14 x 72.25
A = 226.865

answer <span>226.9 m² (third choice)</span>

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Julie and her brother go to Atlanta to ride the SkyView Ferris wheel. It measures 200 feet in diameter.
Law Incorporation [45]

Answer:

Question 1: A)we need to use the CIRCUMFERENCE.

B) Circumference of a Circle  = 2 π R

c)The distance traveled in 1 rotation  =  628 ft

2(a)AREA of a CIRCLE   = π  R²

(b)Area the wheel takes up is 31,400 sq ft

Step-by-step explanation:

Question 1:

Diameter  = 200 ft

Now,as Diameter = 2 x Radius

So, R  = D/2 =200/2 = 100 ft

A) Distance around the wheel = The length of the boundary of the wheel.

So, we need to use the CIRCUMFERENCE.

B) Circumference of a Circle  = 2 π R

Here R = Radius and use π =  3.14

C) The distance traveled in 1 rotation = 1 completer length of  boundary

Now, Circumference  = 2 π R = 2 x (3.14)  x (100 ft)  = 628 ft

Question 2:

A) Space the Ferris Wheel takes up   = Area of the wheel

AREA of a CIRCLE   = π  R²

B) AREA of a CIRCLE   = π  R²

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3 0
3 years ago
An article in American Demographics claims that more than twice as many shoppers are out shopping on the weekends that during th
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X is N(85, 20)

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Z=\frac{x-85}{20}

a) the probability that he has spent more than $95 at the mall

=P(X>95) = P(Z>0.5)=\\0.5-0.1915\\=0.3085

b.  the probability that he has spent between $95 and $115 at the mall

=P(95

c. If two shoppers are randomly selected, what is the probability that both shoppers have spent more than $115 at the mall

=product of two probabilities since independent

= {P(X>115)}^2\\= P(Z>1.5)*P(Z>1,5)\\= 0.0668^2\\=0.0045

7 0
3 years ago
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