I'm sorry I would help but I'm going to have to say b sorry for not being able to show
The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
Learn more about least common multiple here
brainly.com/question/11533141
#SPJ4
Given:
A number line from -10 to 10 with 20 tick marks.
Point D is 1 tick mark to the left of 5.
To find:
The integer value that represents point D.
Solution:
A number line from -10 to 10 with 20 tick marks. It means, each mark represents the integer values from -10 to 10.
We know that, as we move towards left on a number line the value decreases and as we move towards right the value increases.
Point D is 1 tick mark to the left of 5. It means, point D represents the integer value which is 1 less than 5.
Therefore, point D represents the integer 4.
Answer:
the third one
Step-by-step explanation:
p n p is p
p n q is p
q n q is q
q n p is p
p: true
q: false
got it?
if u download photomath and take a picture of each problem it will give u a solution to each problem along with the steps of how they got that answer
