All categories

3 years ago

Write an equation for the translation of x2 + y2 = 49 by 3 units left and 4 units up

1 answer:

3 0

Your equation is a circle. To manipulate the graph upwards or downwards, you would add or subract to the Y-value. To manipulate the graph left or right, add or subtract to the X-value.

So your new equation should be:

$(x-3)^{2} + (y+4) ^{2} = 49$

You might be interested in

Gideon took an online math test consisting of 25

kondor19780726 [428]

Step-by-step explanation:

25 questions, 2 points each.

that means there were 25×2 = 50 points in total.

Gideon got 42 out of the 50.

100% = 50

1% = 100%/100 = 50/100 = 0.5

42 is how many % ? as many as 1% (0.5) fits into 42.

so,

42/0.5 = 42×2 = 84%

he scored 84%.

5 0

2 years ago

Please help me <br>i beg you <br>PLEASE HELP ME ASAP <br><br>I SWEAR TO GOD WILL MARK YOU BRAINIEST

daser333 [38]

Step-by-step explanation:

DEFINITION: Besting: the clockwise totation (0° to 360°) from North to any line.

A) Calculate the bearings of D from A:

bearings of D from A =x

looking the picture:

x=48°+55°+180°

x+103°+180°

x=283°

B)Calculate the bearings of A from C:

bearings of A from C =y

180°+55°=y

y=235°

C) Calculate the distance between A and B:

The angle in B is 74° (Because 55°+51°+74°=180°)

Using the Law of sines:

$\frac{19}{sin(74)} =\frac{AB}{sin(51)} \\\\AB=19sin(51)sin(74)\\AB=14,2\\\\$

D)Calculate the distance between D and C:

Using the Law of cossines:

$DC^{2} =27^{2} +19^{2} -2*27*19*cos(48)\\DC=20,09$

E) A Helicopter is hovering at A at a height of 2.5Km, find angle of elevation of helicopter from C:

The triangle HBA is rectangle

$\alpha =arctan(\frac{2,5}{19})$

α=7,49°

5 0

3 years ago

Please help 25 points and brainiest

Archy [21]

Answer:

what i would do is look them up on a calculator if you have a calcoulater

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

All steps for: x/x-2 + x-1/x+1= -1

lorasvet [3.4K]

Answer:

$\large\boxed{x=0\ \vee\ x=1}$

Step-by-step explanation:

$Domain:\\\\x-2\neq0\ \wedge\ x+1\neq0\\\\x\neq2\ \wedge\ x\neq-1\\\\\boxed{D:\ x\in\mathbb{R}-\{-1,\ 2\}}\\\\=============================$

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1\qquad\text{subtract}\ \dfrac{x-1}{x+1}\ \text{from both sides}\\\\\dfrac{x}{x-2}=-1-\dfrac{x-1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)}{x+1}+\dfrac{-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-x-1-x+1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-2x}{x+1}\qquad\text{cross multiply}$

$x(x+1)=-2x(x-2)\qquad\text{use the distributive property}\\\\(x)(x)+(x)(1)=(-2x)(x)+(-2x)(-2)\\\\x^2+x=-2x^2+4x\qquad\text{add}\ 2x^2\ \text{to both sides}\\\\3x^2+x=4x\qquad\text{subtract 4x from both sides}\\\\3x^2-3x=0\qquad\text{distributive}\\\\3x(x-1)=0\iff 3x=0\ \vee\ x-1=0\\\\x=0\in D\ \vee\ x=1\in D$

4 0

3 years ago

Read 2 more answers

What are the possible roots to √ ̅225 ?

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

15 times 15 equals 225

7 0

4 years ago