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-Dominant- [34]

3 years ago

7

Hailey wants to hire someone to paint her house. She researched several independent painters who provided information about the

average amount of time it takes them to paint a certain number of square feet of wall space. The three painters with the top ratings are listed in the table below, along with the information they provided.
Name Area Painted
(square feet) Time
(hours:minutes)
Richard 288 45
Gerard 825 2:12
Matthew 992 2:35

Part A: Calculate the unit rate for each painter.

Part B: Compare each pair of painters (Richard with Gerard; Gerard with Matthew; Matthew with Richard), and state whether their rates are in a proportional relationship or not (and why) using their respective unit rates as evidence.

1 answer:

Reika [66]3 years ago

6 0

Answer:

my name is hailey

Step-by-step explanation:

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riadik2000 [5.3K]

Answer:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

Step-by-step explanation:

Incomplete question:

<em></em> $\angle CBD = 53^\circ$ <em></em>

<em></em> $\angle CAB = 35^\circ$ <em></em>

<em></em> $AB = 75$ <em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

$\angle ABC + \angle CBD = 180$ --- angle on a straight line

$\angle ABC + 53= 180$

Collect like terms

$\angle ABC =- 53+ 180$

$\angle ABC =127^\circ$

$\angle ABC + \angle ACB + \angle CAB = 180$ --- angles in a triangle

$\angle ACB + 127 + 35 = 180$

Collect like terms

$\angle ACB =- 127 - 35 + 180$

$\angle ACB =18$

Apply sine rule

$\frac{\sin A}{a} = \frac{\sin B}{b}$

In this case:

$\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}$

This gives:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

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3 years ago

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Step-by-step explanation:

Because 7.7^2 equals 60,

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Answer:

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Step-by-step explanation:

8=8p+13-3p

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Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5-6}{0.2}$

$Z = -5$

$Z = -5$ has a pvalue of 0.

1 - 0 = 1

5 0

3 years ago