We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
(3x^3 - 4y^3) ( 3x^3 + 4y^3)
Step-by-step explanation:
9x^6 – 16 y^6
Rewriting as
(3x^3) ^2 - ( 4y^3) ^2
This is the difference of squares a^2 - b^2 = (a-b)(a+b)
(3x^3 - 4y^3) ( 3x^3 + 4y^3)
Answer:
x= 1 program
x= $2
Step-by-step explanation:
40-30= 10 <- what she spent
10/5 = 2
5 = Amount of Programs
Each program is $2.
Your welcome :)
Square root means 46225^1/2 so the answer is 65
