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3 years ago

How do I find the prime factorization least common multiple and greatest common multiple

Mathematics

1 answer:

Elenna [48]3 years ago

8 0

You do this by making a factor tree

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Missing Angles in Triangles Worksheet

stira [4]

Answer:

Step-by-step explanation:

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3 years ago

Which ratio can be used to solve for y in the triangle below?

Crank

Answer:

sin75/25=sin40/y

Step-by-step explanation:

sin75/25=sin40/y

you can use cross products to solve but since you didn't ask for solving I will just give you the ratio :)

please mark me brainliest :)

5 0

3 years ago

Read 2 more answers

A shipping container can hold a maximum of 3,000 pounds of cargo how many 150 lb boxes can go inside the container?

Bond [772]

20 boxes can fit inside

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3 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Fed [463]

Answer:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

Step-by-step explanation:

Factor constant terms:

$-2(-4sin(2\theta)+sin(\theta))=0$

Divide both sides by -2:

$sin(\theta)-4sin(2 \theta)=0$

Expand trigonometric functions using the fact:

$sin(2 \theta) =2 sin(\theta) cos(\theta)$

So:

$sin(\theta) -8sin(\theta)cos(\theta)=0$

Factor sin(x) and constant terms and multiply both sides by -1:

$sin(\theta) (8cos(\theta)-1)=0$

Split into two equations:

$(1)=8cos(\theta)-1=0\\\\(2)=sin(\theta)=0$

For (1)

Add 1 to both sides and divide both sides by 8:

$cos(\theta)=\frac{1}{8}$

Take the inverse cosine of both sides:

$\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z$

For (2)

Simply take the inverse sine of both sides

$\theta = k \pi, \hspace{3}k\in Z$

Therefore, the solutions are given by:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

8 0

3 years ago

What is the rate of change between the point (0,0)and (2,100)

Ivenika [448]

The answer would just be 50/1 or just 50

8 0

3 years ago