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Lana71 [14]
3 years ago
6

what is the formula for calculating the circumference, C, of a circle, if you know pi and the diameter

Mathematics
2 answers:
Karolina [17]3 years ago
8 0

Answer: The formula for calculating the circumference is C = pie(d)

or you could also use C = 2(pi)r squared.

stich3 [128]3 years ago
7 0
The circumference would be diameter times Pi
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Which shows the image of quadrilateral ABCD after the transformation R0, 90°?
avanturin [10]

Answer:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

Step-by-step explanation:

The coordinates of rectangle ABCD are A(-1,0), B(0,-1), C(-2,-3), (-3,-2).

The mapping for a rotation through 90° clockwise about the origin is

(x,y)\to ( - y,x)

Therefore:

A(-1,0)\to A'(0,-1)

B(0,-1)\to B'(1,0)

C(-2,-3)\to C'(3,-2)

D(-3,-2)\to D'(2,-3)

Therefore the image rectangle has coordinates:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

The first choice is correct.

4 0
2 years ago
Read 2 more answers
How many positive integers less than 500 are equal to 5 times an even integer?
arlik [135]

Answer:

490/10=49

Every 10 numbers is one number. I divided by 490 because it says less then 500

Step-by-step explanation:

4 0
2 years ago
5TH GRADE MATH Find the percent of increase:
Tpy6a [65]

Answer:

2.4

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
ABC was dilated to create A' B' C'. What is the center of dilation? And what is the scale factor of the dilation?
Virty [35]

Given:

In the given figure the vertices of triangle ABC are A(-2,2), B(4,2), C(-2,-2).

The vertices of triangle A'B'C' are A'(-4,4), B'(8,4), C'(-4,-4).

To find:

The center of dilation and the scale factor.

Solution:

In the given graph, draw the lines AA', BB' and CC'. The intersection point of these lines is the center of dilation.

From the below graph, it is clear that the lines AA', BB' and CC' intersect each other at (0,0).

Therefore, the center of dilation is (0,0).

If a figure is dilated by factor k and the center of dilation is origin, then

(x,y)\to (kx,ky)

A(-2,2)\to A'(k(-2),k(2))

A(-2,2)\to A'(-2k,2k)

It is given that A'(-4,4). So,

(-2k,2k)=(-4,4)

On comparing both sides, we get

-2k=-4

2k=4

k=\dfrac{4}{2}

k=2

Therefore, the scale factor is 2.

4 0
3 years ago
What is the equation for the line that passes through the points (-2,1) and (1,-11)
givi [52]

Answer:

y=4x+7

Step-by-step

(-2,1) and (1,-11)

1)Rule you should use is run over rise aka slope

y²-y^1=

x^2-x^1=

(-11)-1=12

1-(-2)=3

12/3=4

slope =4

2)Rule of point slope intercept

y - y1 = m(x - x1)

y+1=4(x+2)

y+1=4x+8

   -1     -1

y=4x+7

8 0
2 years ago
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