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ozzi
3 years ago
5

Solve the equation. у+ 3 = -у +9 Оy = 1 Оy= 3 O y=6 Оy= 9

Mathematics
2 answers:
Triss [41]3 years ago
5 0

Answer:

y = 3

Step-by-step explanation:

Solve for y:

y + 3 = 9 - y

Add y to both sides:

y + y + 3 = (y - y) + 9

y - y = 0:

y + y + 3 = 9

y + y = 2 y:

2 y + 3 = 9

Subtract 3 from both sides:

2 y + (3 - 3) = 9 - 3

3 - 3 = 0:

2 y = 9 - 3

9 - 3 = 6:

2 y = 6

Divide both sides of 2 y = 6 by 2:

(2 y)/2 = 6/2

2/2 = 1:

y = 6/2

The gcd of 6 and 2 is 2, so 6/2 = (2×3)/(2×1) = 2/2×3 = 3:

Answer:  y = 3

____ [38]3 years ago
5 0

Answer:

y=3

Step-by-step explanation:

y+3=-y+9

(3)+3=-(3)+9

3+3=6

-3+9=6

6=6

So the answer will be B or y=3

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Parsons Bank offers two​ checking-account plans. The No Frills plan charges
7nadin3 [17]

If the number of checks are greater than 25, the Simple Checking plan cost​ less.

We have two checking account plans at Parson's bank.

We have to determine for what number of checks per month will the Simple Checking plan cost​ less.

<h3>What is an Inequality in Mathematics ?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Let for x number of checks per month the simple checking plan cost less.

For No frills plan -

Charge per check - $0.25

Therefore, for x checks, it will cost - $0.25x

For Simple Checking plan -

Fixed monthly charges - $5

Charges per check - $0.50

Therefore - for x checks - $5 + $0.50x

Now - for Simple Checking plan to cost​ less than No frills plan -

5 + 0.05x < 0.25x

5 < 0.25x - 0.05x

5 < 0.2x

x > 25

Hence, if the number of checks are greater than 25, the Simple Checking plan cost​ less.

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3 0
1 year ago
Can the remainder in a division problem ever equal the divisor? explain why or why not.
erastovalidia [21]
No, cause the remainder might be bigger than divisor.
5 0
2 years ago
Read 2 more answers
If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then
agasfer [191]

Answer:

smaller value is 1.2

larger value is 6

Step-by-step explanation:

f(x)=\frac{3}{1+x^{2} }

when x=a=0, one has

f(0)=\frac{3}{1+0^{2} } \\f(0)=3

now, when x=b=2, one has

f(2)=\frac{3}{1+2^{2} } \\f(2)=\frac{3}{5}

Therefore, the absolute minumun is

m=\frac{3}{5}

and the absolute maximun is

M=3

The approximation to the integral is

\frac{3}{5}(2-0)\leq \int\limits^2_0 {f(x)} \, dx  \leq 3(2-0)

hence

\frac{3}{5}(2)\leq \int\limits^2_0 {f(x)} \, dx  \leq 3(2)\\\frac{6}{5} \leq \int\limits^2_0 {f(x)} \, dx  \leq 6\\1.2 \leq \int\limits^2_0 {f(x)} \, dx  \leq 6

7 0
3 years ago
Help is needed!!! please
Ede4ka [16]

Answer:

5

Step-by-step explanation:

There are 2 ways to look at this. I will explain both.

First we have the 3-4-5 triangle method, stating that any triangle with sides 3 and 4 will have the last side as 5.

Now, for the more complex way of doing this, we can use the Pythagorean theorem to solve this problem.

Pythagorean theorem: a^2+b^2=c^2

We can use 4 for a and 3 for b

You will now have

4^2+3^2=c^2\\\\16+9=c^2\\25=c^2

Then take √25, or 5.

3 0
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Jet found 40 dirty trash bins. She cleaned 15 of the bins, then found another 12 that were dirty. She wants to clean them all. H
fgiga [73]
40-15= 25. 25+12= 37. she wants to clean 37.
8 0
2 years ago
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