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3 years ago

Answer please need help

Mathematics

2 answers:

a_sh-v [17]3 years ago

8 0

Answer:

-7

Step-by-step explanation:

iren2701 [21]3 years ago

3 0

You have to divide both sides by -2, which gets you r = -7 as your answer

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

What is the simplest form of 3^ √27t^9/729?

Natali [406]

Answer:

$\frac{t^{3} }{3}$

Step-by-step explanation:

$\sqrt[3]{\frac{27t^{9} }{729} }$ 27 is a perfect cube for $3^{3}$ and 729 is a perfect cube for $9^{3}$

$\sqrt[3]{\frac{3^{3} t^{9} }{9^{3} } }$ now you can pull out the numbers from under the root, for t (divide the exponent by 3)

$\frac{3}{9}$ $t^{3}$ now simply to $\frac{t^{3} }{3}$

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Answer:

Step-by-step explanation:

42 divided by 3 is 14

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Basically you want to find an equivalent fraction for 3/5 in the answer choices.

12/20 equals 3/5 because 3/5 x 4/4 (or 1) = 12/20

answer: 4

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3 years ago

What is 3/4 divided by 1/3

mash [69]

Answer:

2.25

Step-by-step explanation:

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