The surface area to volume ratio will be higher as compared to the parent cell after cell division. Hence, option B is correct.
Further Explanation:
Cellular division is known to be the process through which the parental cell segregates into two or more daughter cells. This process generally occurs as a segment of a larger cell cycle. It comprises of 2 main stages, interphase and M-phase. Interphase is further segregated into:
- G1 phase wherein the cell prepares itself for the upcoming events.
- S phase is the phase where DNA synthesis occurs
- G2 phase is the phase wherein the cell gets ready for the M phase.
M phase or mitotic phase is the next stage after interphase and is segregated into 4 phases:
- Prophase is the first event which occurs and in this the nuclear envelope disappears, mitotic spindle formation starts, and chromosome condensation begins.
- Metaphase is wherein the alignment of chromosome occurs on the equatorial plate.
- Anaphase is the phase wherein the chromosomes segregate towards the opposite ends
- Telophase is the final stage and division of the two daughter cells is completed.
During cellular division, the cell segregates into 2 daughter cells and as the cell becomes larger, the volume elevates rapidly as compared to its surface area. Hence, option B is correct. The reduction in the cell’s ration of the volume to surface area makes it difficult for the cell to transport the required substances in and move out the waste products quickly enough for the cell to survive.
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Answer Details:
Grade: High school
Subject: Biology
Chapter: Cell Division
Keywords:
Cell division, cellular division, interphase, cell cycle, metaphase, M phase, G1 phase, prophase, G2 phase, telophase, S phase, anaphase, surface area, volume, ratio.