1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iris [78.8K]
2 years ago
5

Rob draws 16 cards from a standard deck of 52. The deck is made up of equal numbers of four suits- clubs, diamonds, hearts, and

spades. How many of the cards drawn can Rob expect to be spades?
Mathematics
1 answer:
alexira [117]2 years ago
8 0
Sixteen plus fifty two equals 68
You might be interested in
What is the domain of the function shown on the graph?
blondinia [14]

Answer:

Step-by-step explanation:

Looking at the arrows on the graph, it appears that as the graph keep growing UP unbounded, it also keeps growing to the left unbounded (to negative infinity, to be exact). Looking to the right, it appears that as the graph decreases unbounded (the y values keep getting smaller), the graph keeps growing in the x direct to positive infinity. So the domain is

- ∞ < x < ∞

4 0
3 years ago
Evaluate: a-2b/c : if a = -8, b = 6.5, and c = -2.<br><br> -1.5<br><br> 10.5<br><br> -9
Mkey [24]
The answer to ur equation is  -1.5
3 0
3 years ago
Read 2 more answers
The ratio of Tom's studying time on a weekday to his studying
lesantik [10]

Answer:

6 hrs

Step-by-step explanation:

4:5

2.4 : 3.2

2.4+3.2=6 hrs

6 0
2 years ago
Read 2 more answers
Assume that when adults with smartphones are randomly​ selected, 63​% use them in meetings or classes. If 7 adult smartphone
nlexa [21]

Answer:

5.78% probability that exactly 2 of them use their smartphones in meetings or classes.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

63% use them in meetings or classes.

This means that p = 0.63

7 adult smartphone users are randomly selected

This means that n = 7

Find the probability that exactly 2 of them use their smartphones in meetings or classes.

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{7,2}.(0.63)^{2}.(0.37)^{5} = 0.0578

5.78% probability that exactly 2 of them use their smartphones in meetings or classes.

8 0
2 years ago
Giving the right answer a branleist
balu736 [363]

Answer:

GCF is 8

Step-by-step explanation:

4 0
2 years ago
Other questions:
  • Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
    15·2 answers
  • Simplify the expression x(2x + 3) + (x - 3)(x - 4)
    8·1 answer
  • A city has two water towers. One tower holds 7.35 x 105 gallons of water and the other tower holds 9.78 x 105 gallons of water.
    12·1 answer
  • 2/8 is what as a decimal
    13·1 answer
  • The nearest tenth to 555.55
    13·1 answer
  • What is 4/9 divided by 8/15
    12·2 answers
  • Someone please saveee meee on this :(
    15·2 answers
  • Necesito que me ayuden con unas tareas de matematicas de primer grado de secundaria​
    12·1 answer
  • 1 1 point Point A and Point B are on the number line. Point A is at-8 and Point B is at 2. Where is the midpoint?​
    5·1 answer
  • A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!