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blsea [12.9K]
3 years ago
15

What is a common factor?

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
Factors are the numbers you multiply together to get another number. When you find the factors of two or more numbers, and then find some factors are the same ("common"), then they are the "common factors<span>"

</span>Example: 12 and 30
• The factors of 12 are: 1, 2, 3, 4, 6 and 12
• The factors of 30 are: 1, 2, 3, 5, 6, 10, 15 and 30
<span>So the common factors of 12 and 30 are: 1, 2, 3 and 6
</span>
-Hope this helped.
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Solve 12−5x−4kx=y for x.
IgorC [24]

Answer:

x = \frac{12-y}{4k+5}

Step-by-step explanation:

12-5x-4kx=y

1. Subtract 12 from both sides.

2.Distrubutive property (factor) a(b+c)=ab+ac

x(-5-4k)=y-12

  • Divide by -5-4k

x = \frac{y-12}{-5-4k}

= \frac{12-y}{4k+5}

5 0
3 years ago
The line L passes through the points (0, –2) and (6, 1).<br><br> Find an equation of the line L.
lesya692 [45]

Answer:

Some Facts about lines (1) For non vertical line L, if L passes a point (x0,y0) with slope m, then an equation of line L is y − y0 = m(x − x0). (2) If a non vertical line L passes through distinct points (x1,y1) and x2(y2), then the slope of L is m = y2 − y1 x2 − x1 . x a + y b = 1.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!!!! EASY MATH 25 PTS
Harman [31]

its not worth 25 points but ok here u go let's solve your equation step-by-step.

3y−1=13−4y

Step 1: Simplify both sides of the equation.

3y−1=13−4y

3y+−1=13+−4y

3y−1=−4y+13

Step 2: Add 4y to both sides.

3y−1+4y=−4y+13+4y

7y−1=13

Step 3: Add 1 to both sides.

7y−1+1=13+1

7y=14

Step 4: Divide both sides by 7.

7y

7

=

14

7

y=2

Answer:

y=2 so there your answer is this equation has one solution  your welcome

4 0
2 years ago
Read 2 more answers
Evaluate f(x)3x + 8 for x = 1.<br><br> A. -11<br> B. 5<br> C. 11<br> D. 3
mariarad [96]

Answer:11

Step-by-step explanation:

f(x)=3x+8

f(1)=3(1)+8

f(1)=3+8

f(1)=11

5 0
2 years ago
What is the inverse of f(x)=e^x
enot [183]

Answer:

f^{-1}(x)=\ln{x}

Step-by-step explanation:

An <em>inverse</em> function is any function that "undoes" another function. If we think of the function f as some kind of machine that takes in a number x as input and produces a number f(x) as an output, when we give inverse function f^{-1} the number f(x) as in input, we get x, our original input, as the output f^{-1}(x)

We need a function that undoes f(x)=e^x, and the natural choice for undoing an exponent is with a logarithm. Here, our base is e, so we'll choose \log_e{x}=\ln{x} as our inverse function. Let's see how that works:

f^{-1}(f(x))=\ln{e^x}

\ln{e^x} is the power we have to raise e to to get e^x, which is x, so

f^{-1}(f(x))=\ln{e^x}=x

And we have our function.

8 0
3 years ago
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