In basketball you score 2 points for a field goal and 1 point for a free throw. Suppose that you have scored at least 3 points i
n every game this season, and have a high season score of 15 points in one game. How many field goals and free throws could you have made in any one game?
2x + y ≤ 15
x + y ≥ 3
write one possible solution to the problem in sentence form
2x + y ≤ 15
x + y ≥ 3
write one possible solution to the problem in sentence form
2 answers:
Answer:
There are 2 points for a field goal, and 1 point for a free throw.
x=Points scored for a field goal
y=Points scored for a free throw
It is also given that, you have scored at least 3 points in every game this season, and have a high season score of 15 points in one game.
2x+y≤15
x+y≥3
Plotting the inequality on two dimensional xy plane
The solution set through graph is attached below.
One possible solution is
x=5 field goals
y=5 free throw
⇒In a game I have made 4 field goals and 3 free throws. So total number of points scored in game will be 4×2+3=11 points.
You might be interested in
Answer: choice 2) SAS
AB = DE is one pair of congruent sides that forms the first S in SAS. The other S in SAS refers to the pair of congruent sides BC = EF. The A in SAS is the angle pair angle B = angle E. Note how angle B and angle E are between the two pairs of congruent sides. The order of the letters matters because SAS is different from SSA, which is not a valid congruence argument. Check out the attached image.
