Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
(a)
here m = - 
and c = 6, hence
y = - x + 6 ← equation of line
(b)
here m = 6, hence
y = 6x + c ← is the partial equation
to find c substitute (2, - 6 ) into the partial equation
- 6 = 12 + c ⇒ c = - 6 - 12 = - 18
y = 6x - 18 ← equation of line
(c)
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (- 1, 3) and (x₂, y₂ ) = (4, 7)
m = 
= 
, hence
y = x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (- 1, 3 ), then
3 = - + c → c = 3 + = 
y = x + ← equation of line
Answer:
Step-by-step explanation:
infinite and no solutions
When you subtract a negative, it changes it to adding a positive.
= -2.5 - (-3.25)
= -2.5 + 3.25
= 0.75
Hope This Helped! Good Luck!
