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Murljashka [212]
4 years ago
14

is it true when a linear function eventually exceeds a quadratic function with a positive leading coefficient

Mathematics
1 answer:
Serjik [45]4 years ago
4 0
I think you yes it does because,<span>Systems consisting of </span>a linear<span> equation and a quadratic equation ... Interpret parts of an expression, such as terms, factors, and coefficients. ..... a </span>Leading Coefficient<span> of 1: .... </span>eventually exceed<span> the growth rates of the other.

</span>
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The speed that a tsunami can travel is modeled by the equation s = 356 startroot d endroot , where s is the speed in kilometers
Naddika [18.5K]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

<h3>What is speed?</h3>

Speed can be calculated as the ratio of distance traveled to the time taken.

The speed that a tsunami can travel is modeled by the equation

s = 356√d, where s is the speed in kilometers per hour and d is the average depth of the water in kilometers.

S = 356√d

200 = 356√d

√d = 200/356

= 0.5618

d = 0.5618^2

= 0.316 km

d = 0.32 km.

Thus, The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

Learn more about speed;

brainly.com/question/4723349

8 0
2 years ago
Dylan delivers parcels.
vovikov84 [41]

Answer:

Dylan delivered 140 parcels on Wednesday.

Step-by-step explanation:

On Wednesday:

On Wednesday, he delivered x parcels.

Thursday:

10% more than Wednesday, so 100 + 10 = 110% of x = 1.1x

Friday:

50% pless than on Thursday, so 100 - 50 = 50% of 1.1x = 0.5*1.1*x.

THis is equals to 77. So

0.5*1.1x = 77

x = \frac{77}{0.5*1.1}

x = 140

Dylan delivered 140 parcels on Wednesday.

5 0
3 years ago
 Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).
Alisiya [41]
p(x)=2x^4-3x^2+x-1\\\\&#10;Substitude\ p=-1\ into\ equation\\\\&#10;p(-1)=2x^4-3x^2+x-1=2*(-1)^4-3(-1)^2-1-1=\\2*1-3*1-2=2-3-2=-3\\Answer\ p(-1)=-3
7 0
3 years ago
A stick 1 meter long casts a shadow 0.6 meters long. A building casts a shadow 25 meters long. How tall is the building (to 2 de
zloy xaker [14]

Answer:

41.67

Step-by-step explanation:

Using the tangent on the stick with shadow:

tan(θ) = \frac{1}{0.6}

Using the tangent on the building:

tan(θ) = \frac{h}{25}

⇒ h = 25 · tan(θ)

       = 25 · \frac{1}{0.6}

⇒ h = 41.66... ≈ 41.67

8 0
3 years ago
The blue lake trail is 11 3/8 miles long. Gemma has hiked 2 1/2 miles each hour for 3 hours. How far is she from the end of the
melomori [17]
In the question it is given that the length of the blue lake trail is 11 3/8 miles. In the question it is also given that Gemma has hiked for a total time of 3 hours and each hour she has hiked 2 1/2 miles.
Now coming to solving the problem we get:
Total length of blue lake trail = 11 3/8 miles
                                             = 91/8 miles
Distance hiked by Gemma in 1 hour = 2 1/2 miles
                                                           = 5/2 miles
Then the total distance hiked by Gemma in 3 hours = (5/2) * 3
                                                                                   = 15/2 miles
The distance left to cover the full trail = (91/8) - (15/2) miles
                                                            = (91 - 60)/8 miles
                                                             = 31/8 miles
                                                             = 3 7/8 miles.
So Gemma is 31/8 miles or 3 7/8 miles from the end of the trail.
7 0
3 years ago
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