Imagine you covered the outer part of the wheel with paint. Then you rolled the wheel one complete revolution. The paint on the wheel would transfer to the flat ground making a straight line. The length of this straight line is exactly equal to the distance around the circle (aka circumference)
Let's find the circumference
C = 2*pi*r
C = 2*pi*14
C = 28pi
The distance around the circle is exactly 28pi inches.
If we use pi = 3.14, which is an approximation of pi, then that approximates to 28*pi = 28*3.14 = 87.92
So one revolution corresponds to traveling 87.92 inches approximately
We want to travel 440 inches. The question is: how many revolutions do we need to go in order to achieve this goal?
Let k = number of revolutions needed to travel 440 inches
1 revolution = 87.92 inches traveled
k revolutions = k*87.92 inches traveled
Set the expressions k*87.92 and 440 equal to each other and solve
k*87.92 = 440
k*87.92/87.92 = 440/87.92
k = 5.0045495 ... this is approximate
So it takes about 5 revolutions to travel 440 inches. We'll need a bit over 5 to make sure we get to 440.
Final Answer: Choice B) 5 rotations
7
:):):):)
:):):):)
Sxcbnheaaaqsfvbjj
Answer:
o.2m.
s=av/t where av= average speed and s= speed and t= time
Answer:
y-8=5(x-4)
Step-by-step explanation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(-2-8)/(2-4)
m=-10/-2
m=10/2
m=5
y-8=5(x-4)
Answer:
= 72a + 20s
Step-by-step explanation:
Given that;
a = number of adult tickets sold
s = number of student tickets sold.
According to given condition:
For first night;
=2(9a) + 5s
=18a + 5s
For second night:
= 3*18a + 3*5s
= 54a + 15s
Expression for total money of both nights:
= (18a + 5s ) + (54a + 15s )
Adding same terms:
= 72a + 20s
i hope it will help you!
