Question

The product of two consecutive positive integers is 812. What is the value of the lesser integer? a. 7 b. 28 c. 58 d. 203

Answer 1

Answer:

The value of the lesser integer is $28$

Step-by-step explanation:

Let two consecutive positive integers be $x,x+1$.

Product of two consecutive positive integers = $x(x+1)=x^2+x$

Also, product of two consecutive positive integers is 812

So,

$x^2+x=812\\x^2+x-812=0\\x^2+29x-28x-812=0\\x(x+29)-28(x+29)=0\\(x-28)(x+29)=0\\x=28,-29$

As $x$ is a positive integer,

$x=-29$ is rejected.

So,

$x=28\\x+1=28+1=29$

Two positive integers are $28,29$

The value of the lesser integer is $28$

Answer 2

Answer:

B

Step-by-step explanation: