3 years ago

Someone please help on this

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

$x - 6 = 5(x + 2) \\ x - 6 = 5x + 10 \\ x - 5x = 10 + 6 \\ - 4x = 16 \\ x = - 4$

You might be interested in

How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled

spayn [35]

The volume of oblique cone = $\frac{1}{3} \pi r^{2} h$

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = $\frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)$

= $\frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )$ $=4*(\frac{1}{3} \pi r^{2} h )$

It means the volume becomes 4 times

3 0

3 years ago

What is the value of x that makes the given equation true? x−3x=2(4+x)

Margarita [4]

the answer to your question is x= -2

5 0

3 years ago

Read 2 more answers

Aisha helps out at a petting zoo over the summer. She makes some changes where the animals are kept.

adoni [48]

I believe the awnser is A

3 0

2 years ago

The figure shows △ABC . BD is the angle bisector of ∠ABC .

Misha Larkins [42]

From angle bisector theorem, we know that:

$\dfrac{|AD|}{|DC|}=\dfrac{|BA|}{|BC|}\\\\\\\dfrac{|AD|}{|DC|}=\dfrac{8}{10}=\dfrac{4}{5}$

Moreover:

$|AD|+|DC|=6$

so:

$|DC|=6-|AD|$

and

$\dfrac{|AD|}{|DC|}=\dfrac{4}{5}\\\\\\\dfrac{|AD|}{6-|AD|}=\dfrac{4}{5}\qquad\qquad\text{cross multiplying}\\\\\\ 5\cdot|AD|=4\cdot\big(6-|AD|\big)\\\\5\cdot|AD|=24-4\cdot|AD|\\\\5\cdot|AD|+4\cdot|AD|=24\\\\9\cdot|AD|=24\qquad|:9\\\\\\|AD|=\dfrac{24}{9}=\boxed{\dfrac{8}{3}}$

3 0

3 years ago

Read 2 more answers

In which quadrant does a -285 angle lie

attashe74 [19]

Answer:

first quadrant ( I Quadrant)

3 0

2 years ago