The answer is B x = -4. x= 3
You must factor the equation by find what 2 numbers can multiply to equal -12 and add to equal 1.
-3 and 4 are the two numbers. Now to put it in factor form would be:
(x - 3)(x + 4) = 0
They y also must equal zero.
Since its equals to 0, we must solve for x for the binomial.
x - 3 = 0 ; x = 3
x + 4 = 0 ; x = -4
The answer you get from solving x, is that answer
The answer should be 12 units^2
starting from the left side of the shape you multiply base 2 by height 2 which gets 4 then divide by 2 since it is a triangle. next multiply 2x2 for the square in the middle which gets you 4. lastly multiply 6x2 for the triangle on the right which gets you 12 however bc it is a triangle you must divide by 2 and get 6. then add them all together and you get 12.
Answer:
8w-16
Step-by-step explanation:
8(w-2)
8(w) & 8(-2)
8w-16
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
