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3 years ago

The area of a circle is 55.44 cm2. Find its circumference.

Mathematics

1 answer:

IrinaK [193]3 years ago

8 0

Answer:

Circle

Solve for circumference

C≈26.39cm

A Area

55.44

cm²

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Read 2 more answers

Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund

ser-zykov [4K]

Testing the hypothesis, it is found that since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

$H_0: p = 0.5$

At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

$H_1: p \neq 0.5$

The test statistic is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.
p is the value tested at the null hypothesis.
n is the sample size.

In this problem, the parameters are given by:

$p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482$

The value of the test statistic is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

$z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}$

$z = 2.86$

Since we have a two-tailed test(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

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2 years ago

-2x-2+x^2+x+180+-2x-2=180

Dominik [7]

Answer:

x= 4, -1

Step-by-step explanation:

-2x - 2 + x^2 + x + 180 - 2x - 2 = 180

add like terms and put in descending order

x^2 - 3x + 176 = 180

subtract 180 from both sides

x^2 - 3x - 4 = 0

factor out the equation

(x-4)(x+1)=0

solve for x

x-4=0 x+1=0

x=4 x=-1

5 0

3 years ago