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Colt1911 [192]
2 years ago
15

Whichof the following lists of numbers is in order from greatest to least

Mathematics
2 answers:
Snowcat [4.5K]2 years ago
7 0

Answer:

C I think..................

finlep [7]2 years ago
6 0
It’s c because all the numbers
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Which expression is equivalent to<br> (5^-2)(5^-1)<br> A. -1/125<br> B. -1/5<br> C. 1/125<br> D. 1/5
n200080 [17]

Answer:

1/125

Step-by-step explanation:

(5^-2)(5^-1) = 5^-3=1/5^3=1/125

3 0
3 years ago
25% of 60 75% of 30 50% of 45.7<br> 50% of 60 100% of 22.5<br> 75% of 60 10% of 22.5
alexdok [17]

Answer:

25% of 60 is 15

75% of 30 is 22.5

50% of 45.7 22.85

50% of 60 30

100% of 22.5 is 22.5

75% of 60 is 45

10% of 22.5 2.25

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Write the following equation in standard form: y + 4 = -3(x + 2)
Irina18 [472]

Answer:

-3x-y=10

Step-by-step explanation:

y+4=-3(x+2)

y+4=-3x-6

y=-3x-6-4

y=-3x-10

-3x-y=10

5 0
3 years ago
Math please please please help
kondaur [170]

y=3|3+2|

Hope this helps!

-Payshence

8 0
3 years ago
The proportion of brown M&amp;M's in a milk chocolate packet is approximately 14%. Suppose a package of M&amp;M's typically cont
marshall27 [118]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the scenario above :

A) State the random variable.

The random variable is the p opoertion of brown M&M's in a milk chocolate packet.

B.) Argue that this is a binomial experiment.

Each trial is independent for a total number of 52 trials with a set probability of success at 0.14

C) probability that 6 M&M's are brown:.

P(x) = nCx * p^x * (1-p)^(n-x)

p = 0.14 ; (1 - p) = 0.86 ; n = 52 ; x = 6

P(x = 6) = 52C6 × 0.14^6 × 0.86^46

= 20358520 × 0.00000752954 × 0.00097035078

= 0.1487

D) P(x =25)

P(x = 25) = 52C25 × 0.14^25 × 0.86^27

= 477551179875952 × 449.987958058*10^(-24) × 0.01703955245

= 0.00000000366

E) P(x = 52)

P(x = 52) = 52C52 × 0.14^52 × 0.86^0

= 1 × 3968.78758299*10^(-48) × 1

= 3968.78758299*10^(-48)

F) yes it would be unusual, because such probability is extremely low. However, if a huge or substantial number of trials such may occur

3 0
3 years ago
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