If anyone could help that would be great / right answer gets brainilest
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Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.
Step-by-step explanation:
Since we have given that
Probability that students attend class on Fridays = 70% = 0.7
Probability that who went to class on Fridays would pass the course = 95% = 0.95
Probability that who did not go to class on Fridays would passed the course = 10% = 0.10
Let A be the event students passed the course.
Let E be the event that students attend the class on Fridays.
Let F be the event that students who did not attend the class on Fridays.
Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30
P(A|E) = 0.95, P(A|F) = 0.10
We need to find the probability that they did not attend on Fridays.
We would use "Bayes theorem":
Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.
Since the first term in the equation is 
, you know that each group you make will have to have an x in it. Now, you need to figure out what times what equals 7 and adds up to 8. You can list all of the numbers that multiply to seven until you find the right numbers.
-1 x -7
1 x 7
1 and 7 add to eight and multiply to seven, so those will be the numbers in your groups. This makes your factored groups (x + 1)(x + 7).
-1 x -7
1 x 7
1 and 7 add to eight and multiply to seven, so those will be the numbers in your groups. This makes your factored groups (x + 1)(x + 7).