Answer: H' = (-4, 4)
<u>Step-by-step explanation:</u>
H = (-4, -4)
reflect across y = -2:
H is 2 units below y = -2 so when reflected it will be 2 units above y = -2
--> t<em>he x-coordinate doesn't change</em> the new y-coordinate is: 0
H' = (-4, 0)
reflect across y = 2:
H' is 2 units below y = 2 so when reflected it will be 2 units above y = 2
--> t<em>he x-coordinate doesn't change</em> the new y-coordinate is: 4
H'' = (-4, 4)
You can use the substitution method for this problem
Since -3y+8=x you can
Use the equation -7(-3y+8) -6y=4
You then distribute and solve
21y-56-6y=4
15y=60
Y=4
You then plug y into one of the original equations
X=-12+8
X=-4
(-4,4)
Answer:
A) 7x^2-7x+15
Step-by-step explanation:
f(x) = 4x2 - 5x + 7,
g(x) = 3x2 - 2x + 8
f(x) +g(x) =
4x^2 - 5x + 7 + 3x^2 - 2x + 8=
7x^2-7x+15
34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.



Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
First 4/7 times 7/11 and plus 5,the result of 4/7 times 7/11 equal 4/11,AND THEN 4/11 PLUS 5 EQUAL 5 AND 4/11