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marishachu [46]
3 years ago
10

If anyone could help that would be great / right answer gets brainilest

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
2.69 cm would be the answer
Angelina_Jolie [31]3 years ago
3 0

Answer:

width = 2.9 cm

Step-by-step explanation:

The perimeter of a rectangle = 2l + 2w ( l is the length and w the width )

Here l = 8.3, thus

(2 × 8.3) + 2w = 22.4, that is

16.6 + 2w = 22.4 ( subtract 16.6 from both sides )

2w = 5.8 ( divide both sides by 2 )

w = 2.9

Hence width = 2.9 cm

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The hour hand of a clock moves -30° every hour. How many degrees does it move in 2 1/5 hours?
Andrej [43]
It moves 2.00666666667 every 1 1/5 hours
5 0
3 years ago
The equation (x-6)^2/16 + (y+7)^2/4 = 1 represents an ellipse. What are the vertices of the ellipse?
topjm [15]

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

\frac{(x-6)^2}{16}+\frac{(y+7)^2}{4}= 1

It can be rewritten as

\frac{(x-6)^2}{4^2}+\frac{(y+7)^2}{2^2}= 1         .....(1)

The standard form of an ellipse is

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1           ....(2)

Where (h,k) is center of the ellipse.

If a>b, then the vertices of the ellipse are (h\pm a, k).

From (1) and (2) we get

h=6,k=-7,a=4,b=2

Since a>b, therefore the vertices of the ellipse are

(h+a, k)=(6+4,-7)\Rightarrow (10,-7)

(h-a, k)=(6-4,-7)\Rightarrow (2,-7)

The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.

5 0
3 years ago
Read 2 more answers
Answer the questions by drawing on the coordinate plane below.
solniwko [45]

Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).

a) Let us discuss the rule for rotation of 90° clockwise about the origin.

If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).

x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P'(-1,-1)

Q(3,-2) --> Q'( -2,-3)

R(3,-4) --> R'(-4,-3)

b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P"(1,1)

Q(3,-2) --> Q"( 3,2)

R(3,-4) --> R"(3,4)



6 0
3 years ago
ASAP PLEASE please please
Aleksandr [31]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \cfrac{1}{b}  + 10 =  \cfrac{9}{b}  + 7

\qquad \sf  \dashrightarrow \:  \cfrac{9}{b}  -   \cfrac{1}{b} =  10 -   7

\qquad \sf  \dashrightarrow \:  \cfrac{8}{b}   =  3

\qquad \sf  \dashrightarrow \: b =  \cfrac{8}{3}

5 0
2 years ago
Read 2 more answers
To copy an angle using only a compass and a straightedge, begin by marking the vertex of the new angle. Then draw a ray from the
podryga [215]

The <em>correct answer</em> is:


Place the point of the compass on the vertex of our original angle. Open the compass to a random width and draw an arc through both legs of the angle. Mark the points of intersection with this arc and the sides of the angle.


Explanation:


In order to copy the angle, we need to have some reference for how wide the angle is.


So far all we have is a ray. To get the reference for the width that we need, we will construct an arc in the original angle such that it intersects each side of the angle.


We will then set the compass width to these points of intersection. This will be how we set the width of the new angle.

5 0
3 years ago
Read 2 more answers
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