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bagirrra123 [75]
3 years ago
11

For a snack, sander ate a plum with 32 calories and several strawberries with 4 calories each. If the total number of calories i

s sameer’s snack was 56, how many strawberries did he eat ?
Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

6 strawberries

You subtract 32 from 56, which gives you 24. Then, if one strawberry is 4 calories, you can eat 6 of them to gain 24 calories.

32 + 24 = 56 ... So one plum (32) and six strawberries (4+4+4+4+4+4) gives you 56 calories, which is the total. That's how you can check your work.

Answer: 6

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jeyben [28]
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A bag contains 20 marbles: 12 red, 4 blue, 3 yellow, and 1 green. Arielle takes out 2 marbles. What is the probability that they
Marysya12 [62]

Total number of marbles in the bag =20

Number of blue marbles =4

Now we just want two blue marbles out of four.

Probability of taking out first marble which is blue =4/20

Now after we took out one blue marble , number of blue marbles left are 3.

Probability of taking out second marble which is blue =3/20

Total probability = 4/20 *3/20 = 12/400

So probability of taking out two blue marbles is 0.03 or 12/400.


3 0
3 years ago
Consider the radical equation √n+ 4 = n-2.
muminat

Answer:

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3 0
3 years ago
The equation y = 1725 - 75x represents the amount of money y (in dollars) left in your lunch account after x weeks. 20 weeks go
garik1379 [7]
Y= -75x +1725
y= -75(20) +1725
y = -1500 + 1725
y= 225 = range
225= -75x +1725
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-1500/-75 = -75x/-75
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6 0
3 years ago
If a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter d
grin007 [14]

Answer:

The diameter decreases at a rate of 0.053 cm/min.

Step-by-step explanation:

Surface area of an snowball

The surface area of an snowball has the following equation:

S_{a} = \pi d^2

In which d is the diameter.

Implicit differentiation:

To solve this question, we differentiate the equation for the surface area implictly, in function of t. So

\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}

Surface area decreases at a rate of 3 cm2/min

This means that \frac{dS_{a}}{dt} = -3

Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.

This is \frac{dd}{dt} when d = 9. So

\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}

-3 = 2*9\pi\frac{dd}{dt}

\frac{dd}{dt} = -\frac{3}{18\pi}

\frac{dd}{dt} = -0.053

The diameter decreases at a rate of 0.053 cm/min.

7 0
3 years ago
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