Let the numbers be x and y; x being the larger number and y being the smaller.
Given,
x + y = 2* (x - y)
x + y = 2x - 2y
x = 3y
Also given,
x = 6 + 2y
3y = 6 + 2y
--- y = 6
Thus, x = 3y = 3*6 = 18.
Therefore, the numbers are 18 and 6.
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Answer:
8 people
Step-by-step explanation:
$630-$150= 480
480 divided by 60 dollars= 8 people
Answer:
b.
Step-by-step explanation:I think
Answer:
6
Step-by-step explanation:
-3 x (8 + [-10]) =
-3 x (8 - 10) =
-3 x -2 =
6
HOpe that helps!
