The statement that completes the query is: bytes / 1000 AS kilobytes
<h3>SQL (Structured Query Language)</h3>
This is the language that is used to retrieve, update, and store data in the database.
<h3>Columns</h3>
From the question, we have the following table columns
- track_id
- track_name (name of the music track)
- composer
- bytes (digital storage size of the music track
To retrieve data from the bytes column, we make use of:
SELECT bytes ......
From the question, we understand that this column should be divided by 1000, and the AS command should be used.
So, the query becomes
SELECT bytes / 1000 AS kilobytes .....
Hence, the statement that completes the query is: bytes / 1000 AS kilobytes
Read more about database at:
brainly.com/question/24223730
The most common was is your phone
Answer: C because bill gates is the owner
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
