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Serjik [45]
3 years ago
9

Rush Trainer purchased a houseboat for $165,000. The financing company requires a 15% down payment for a 30-year loan at 7%. At

the end of 30 years, what will be the total amount of interest charged? (Hint: First subtract the down payment from the purchase price to find the amount to be financed.)

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

The answer is $195,508.50

BartSMP [9]3 years ago
6 0

Answer:

The total amount of interest charged is $195,507.6

Step-by-step explanation:

Total Amount = $165000 , No. of months = 12×30 = 360 months ,Down Payment Rate = 15%

Monthly Payment for $1000 loan on 7% interest rate = $6.65

Down\thinspace Payment = 0.15\cdot Total\thinspace Amount\approx 24,750\\\\Amount\thinspace Mortaged=Total\thinspace Amount-Downpayment\\\implies Amount\thinspace Mortaged=165,000-24,750=140,250\\\\Monthly\thinspace Payment=\frac{Amount\thinspace of\thinspace Mortaged}{1000} \cdot Monthly\thinspace payment\thinspace for\thinspace $1000\thinspace loan\\\\\implies Monthly\thinspace Payment=\frac{140250}{1000}\cdot 6.65\approx 932.66\\\\ Total\thinspace Amount\thinspace paid = Monthly\thinspace Payment\cdot No.\thinspace of\thinspace Months\\\implies Total\thinspace Amount\thinspace paid = 932.66\cdot 360\approx 355,757.6$\\\\Total\thinspace interest=Amount\thinspace Paid - Amount\thinspace Mortaged\\\implies Total\thinspace interest=355,757.6-140250\approx 195,507.6

⇒ Total Interest Charged = $195,507.6

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podryga [215]

Answer:

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

p_v =P(t_{(49)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=25.02 represent the sample mean

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =26 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \geq 26  

Alternative hypothesis:\mu < 26  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one sided test the p value would be:  

p_v =P(t_{(49)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

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