Using the factor label method, you would set up your ratio like so:
The amount that the bank loaned out at 7.9% is $1,574.00
How do represent the amounts lent at different rates?
On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate
interest on 7.9% loan=7.9%*x=0.079x
interest on 7.4% loan=7.4%*(8200-x)
interest on 7.4% loan=606.80-0.074x
total interest=0.079x+606.80-0.074x
total interest=0.005x+606.80
total interest on loans=614.67
614.67=0.005x+606.80
614.67-606.80=0.005x
7.87=0.005x
x=7.87/0.005
x=amount loaned at 7.9%=$1,574.00
y=$8200-$1574
y=$6,626.00
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Answer:
Hi! The correct answer is x = -1 y = -1 and the ordered pair is (-1,-1)
Step-by-step explanation:
<em><u>~Solve the first variable in one of the equations, then substitute the result into the other equation~</u></em>
Answer:
$1307.69
Step-by-step explanation:
Let the original investment be x.
Note that a 30% increase in a value is equal to multiplying a value by 130% and a withdrawal is to take out money. The final amount is $1500. Let’s write the equation with the information we have.
Equation:
130%x - 200 = 1500
(130/100)x = 1700
x = 1700(100/130) = $1307.69
I hope this helps! :)
Answer: <em>3.88 to 219</em>
Step-by-step explanation: <em>ok so if the data is O+ donors to B+ donors and you have to write the comparison in three different ways then you look on the chart to see that O+ is 97 & B+ is 25 then it would be 97 to 25. 97 t0 25 & 25 to 97 So I’m thinking next you have to divid 97 by 25 to get 3.88 to 219 . </em>
<em>I might be wrong and if I am i’m sorry.</em>