To solve this problem, we must first convert the distance
into miles:
distance = 60 ft (1 mile / 5280 ft) + 6 inches (1 foot /
12 inches) (1 mile / 5280 ft)
distance = 0.0114583 mile
To calculate for time:
time = distance / speed
time = 0.0114583 mile / (90 miles / 3600 seconds)
time = 0.458 seconds
<span>time = 0.46 seconds</span>
Answer:
1.-6
Step-by-step explanation:
I don't know how to do the second one but
BD = DC
x+8 = 3x+2
2x=-4
x=-2
-6+12
-6
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
-48a÷ 8 can be written as,
Put a=1 in the above exprression and solve.
Therefore, the solution is -6.
Answer:
My net wroth would have changed by $800
Step-by-step explanation:
Because $3,100 - $2,300 = $800
