Question

Plz help!!will give the brainliest!!​

Answer 1

Answer:

x = 3

Inverse matrix:

$A^{-1} = \begin{pmatrix} \frac{1}{9} & \frac{2}{9} \\ \frac{1}{3} & -\frac{1}{3} \end{pmatrix} \quad$

Step-by-step explanation:

Determinant: ad - bc

a = 3, b = 2, c = 3, d = -1

3 * (-1) - (2 * x) = -9

-3 - 2x = -9

-2x = -6

x = 3

For matrix

$A = \begin{pmatrix}a & b\\c & d\end{pmatrix} \quad$

the inverse is

$A^{-1} = \dfrac{1}{ad - bc}\begin{pmatrix}d & -b \\-c & a\end{pmatrix}\quad$

Here we have: det = -9

a = 3, b = 2, c = 3, d = -1

Inverse matrix:

$A^{-1} = \dfrac{1}{-9}\begin{pmatrix} -1 & -2 \\ -3 & 3 \end{pmatrix}\quad$

$A^{-1} = \begin{pmatrix} \frac{-1}{-9} & \frac{-2}{-9} \\\frac{-3}{-9} & \frac{3}{-9}\end{pmatrix} \quad$

$A^{-1} = \begin{pmatrix} \frac{1}{9} & \frac{2}{9} \\\frac{1}{3} & -\frac{1}{3}\end{pmatrix}\quad$

Answer 2

The answer to this question is
x=3
thank you for your time