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Thepotemich [5.8K]
3 years ago
5

A dilation changes the size of an object true or false

Mathematics
1 answer:
slega [8]3 years ago
7 0

Answer:

True. A dilation changes the size of an object but never the shape or position.

Step-by-step explanation:

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Factored form of 2x^2+x-3 must show work
frozen [14]

Answer:

(2x+3)(x - 1)

Step-by-step explanation:

Since there is no common number to factor by we must approach this problem differently:

Step 1:

Multiply leading coefficient (2) by the constant term (-3)

2 x -3 = -6

Step two:

Find two numbers that multiply to -6 but add to the middle coefficient (1).

You should find these numbers to be 3 and -2

Step 3:

Replace 1x in the equation with your found numbers

2x^2 - 2x + 3x - 3

Step 4:

Take out the greatest common factor from the first two numbers, and the last two numbers.

For 2x^2 - 2x the greatest common factor would be 2x

For 3x - 3 the greatest common factor would be 3.

Step 5:

Factor out the found common factors

2x(x-1) + 3(x-1)

The values inside the bracket should be the same.

Step 6:

Factor out (x-1)

(x - 1)(2x + 3)

Therefore the factored form is (2x + 3)(x - 1)

4 0
3 years ago
The Nile River is 6,690 kilometers long. This is 1,160 kilometers longer than the Yangtze River. How long is the Yangzte River?
natta225 [31]
It is 7,850 kilometers long.

4 0
4 years ago
Pls help will give brainliest aubviously
QveST [7]
I believe it is the second one... I think = is for numbers only.
4 0
4 years ago
I need help on this please
Ludmilka [50]

circumference =2πr=2× 7 22  ×28=22×8 =176 cm

Area =πr 2 = 7   22 ×28×28=88×28 =2464 cm 2

<u><em>circumference=176 cm </em></u>

<u><em>Area= 2464 cm 2</em></u>

3 0
3 years ago
The desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5
LekaFEV [45]
Given that t<span>he desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. suppose that the percentage of sio2 in a sample is normally distributed with σ = 0.32 and that \bar{x}=5.24.

</span>
<span>To investigate whether this indicate conclusively that the true average percentage differs from 5.5.



Part A:

From the question, it is claimed that </span><span>t<span>he desired average percentage of sio2 in a certain type of aluminous cement is 5.5</span></span> and we want to test whether the information from the random sample <span>indicate conclusively that the true average percentage differs from 5.5.

Therefore, the null hypothesis and the alternative hypothesis is given by:

H_0:\mu=5.5 \\  \\ H_a:\mu\neq5.5



Part B:

The test statistics is given by:

z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}}  \\  \\ =\frac{5.25-5.5}{0.32/\sqrt{16}} \\  \\ = \frac{-0.25}{0.32/4} = -\frac{0.25}{0.08}  \\  \\ =-3.125



Part C:

The p-value is given by

P(z\ \textless \ -3.125)=1-P(z



Part D:

Because the p-value is less than the significant level α, we reject the null hypothesis and conclude that "</span><span>There is sufficient evidence to conclude that the true average percentage differs from the desired percentage."



Part E:

</span>If the true average percentage is μ = 5.6 and a level α = 0.01 test based on n = 16 is used, what is the probability of detecting this departure from H0? (Round your answer to four decimal places.)

The probability of detecting the departure from H_0 is given by

1-\phi\left(z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right)+\phi\left(-z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right) \\  \\ =1-\phi\left(z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right)+\phi\left(-z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right) \\  \\ =1-\phi\left(z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)+\phi\left(-z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)

=1-\phi\left(z_{0.995}+ \frac{-0.1}{0.08} \right)+\phi\left(-z_{0.995}+ \frac{-0.1}{0.08} \right) \\  \\ =1-\phi(2.576-1.25)+\phi(-2.576-1.25) \\  \\ =1-\phi(1.326)+\phi(-3.826) \\  \\ =1-0.90758+0.00007 \\  \\ =0.0925



Part F:

What value of n is required to satisfy α = 0.01 and β(5.6) = 0.01? (Round your answer up to the next whole number.)

The value of n is required to satisfy α = 0.01 and β(5.6) = 0.01 is given by

n=\left[ \frac{\sigma(z_{0.005}+z_{0.01})}{\mu_0-\mu} \right]^2 \\  \\ = \left[\frac{0.32(-2.576-2.326)}{5.5-5.6} \right]^2 \\  \\ =\left[\frac{0.32(-4.902)}{-0.1} \right]^2=\left[\frac{-1.56864}{-0.1} \right]^2 \\  \\ =(15.6864)^2=247
3 0
4 years ago
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