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aivan3 [116]
3 years ago
15

Ronny, Celina, Jack, and Michelle together placed a total of 20 brownies on a tray. Ronny placed 0.15 of the brownies, Celina pl

aced 3 of the 20 brownies, Jack placed 30% of the brownies, and Michelle placed the remaining brownies. Who placed the most brownies?
Ronny

Celina

Jack

Michelle
Mathematics
2 answers:
earnstyle [38]3 years ago
6 0

Answer:

The right answer is Michelle

Step-by-step explanation:

I TOOK THE TEST!!!

Marat540 [252]3 years ago
3 0
To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
 
Ronny              C1 = 0.15 x 20 = 3
Celina              C2 = 3
Jack                 C3 = 0.30 x 20 = 6
Michelle           C4 = 20 - (3 + 3 + 6) = 8

From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray. 

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Answer:

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Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

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The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

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The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

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