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Arturiano [62]
3 years ago
7

Consider the diagram and angle measurements shown below.

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0
M2 would be (3x-54) just like m5
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What is 3 2/3 x 3/5 ?
telo118 [61]

3 2/3 × 3/5

=> 11/3 × 3/5

=> 11/5

=> 2.2

so your answer is 2.2

3 0
3 years ago
What are objects that are 1 kg
kirill115 [55]

Answer:

One liter of water.

A Pineapple.

A Bunch of Bananas.

A 1 liter bottle of water

6 0
2 years ago
Tony rounded each of the numbers 1, 143 and 1, 149 to the nearest hundred which word correctly compares the rounding numbers
Montano1993 [528]

Full Question:

<em>Tony rounded each of the numbers 1,143 and 1,149 to the nearest hundred. Which choice correctly compares the rounded numbers? </em>

<em></em>1,000 = 1,000

1,140< 1,150

1,100 = 1.100

1,140>1,150

Answer:

1,100 = 1,100

Step-by-step explanation:

Given

1,143 and 1,149

Required

Which of the option is correct

We start by approximating both numbers to nearest digit

<em>1,143; when approximated to nearest hundred is 1,100</em>

<em>1,149; when approximated to nearest hundred is also 1,100</em>

Hence;

1,143 ≅ 1,100

1,149 ≅ 1,100

Comparing both results, we have that

1,100 = 1,100

From the list of given options, option C is correct;

4 0
4 years ago
Find the center,vertices,foci,and asymptotes of the hyperbola.
bogdanovich [222]

Answer:

The center is (8 , -9)

The vertices are (11 , -9) and (5 , -9)

The foci are (8 , -9 + √58) and (8 , -9 - √58)

The equations of the asymptotes are y = 3/7(x − 8) - 9 , y = -3/7 (x − 8) - 9

Step-by-step explanation:

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the y-axis is

  (y - k)²/a² - (x - h)²/b² = 1

- The length of the transverse axis is 2 a  

- The coordinates of the vertices are ( h ± a , k )  

- The length of the conjugate axis is 2 b  

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

- The equations of the asymptotes are y = ± a/b (x − h) + k

* Now lets solve the problem

∵ (y + 9)²/9 - (x - 8)²/49 = 1

∴ h = 8 and k = -9

∴ a² = 9 ⇒ a = ± 3

∴ b² = 49 ⇒ b = ± 7

∵ c² = a² + b²

∴ c² = 9 + 49 = 58

∴ c = ± √58

∵ The center is (h , k)

∴ The center is (8 , -9)

∵ The coordinates of the vertices are ( h ± a , k )

∴ The vertices are (8 + 3 , -9) and (8 - 3 , -9)

∴ The vertices are (11 , -9) and (5 , -9)

∵ The coordinates of the foci are (h , k ± c)

∴ The foci are (8 , -9 + √58) and (8 , -9 - √58)

∵ The equations of the asymptotes are y = ± a/b (x − h) + k

∴ The equations of the asymptotes are y  = 3/7 (x - 8) - 9 and  

   y  = -3/7 (x − 8) - 9

7 0
3 years ago
Read 2 more answers
The total for some groceries at the store was $25.63. With 8% sales tax, what is the total? $
ozzi

Answer:

$2.05

Step-by-step explanation:

just do the math bro

7 0
3 years ago
Read 2 more answers
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