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Savatey [412]
3 years ago
10

Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do

NOT Solve the equation
Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

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